A) \[\log x-\log (1-x)+c\]
B) \[\log (1-{{x}^{2}})+c\]
C) \[-\log x+\log (1-x)+c\]
D) \[\log (x-{{x}^{2}})+c\]
Correct Answer: A
Solution :
\[\int_{{}}^{{}}{\frac{dx}{(x-{{x}^{2}})}=\int_{{}}^{{}}{\left( \frac{1}{x}+\frac{1}{1-x} \right)}\text{ }dx=\log x-\log (1-x)+c}\].
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