JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Integration of Rational Function by Using Partial Fractions

  • question_answer
    \[\int_{{}}^{{}}{\frac{dx}{\cos x-\sin x}}\] is equal to                                           [AIEEE 2004]

    A)                 \[\frac{1}{\sqrt{2}}\log \left| \tan \left( \frac{x}{2}+\frac{3\pi }{8} \right)\, \right|+c\]

    B)                  \[\frac{1}{\sqrt{2}}\log \left| \cot \left( \frac{x}{2} \right)\, \right|+c\]

    C)                 \[\frac{1}{\sqrt{2}}\log \left| \tan \left( \frac{x}{2}-\frac{3\pi }{8} \right)\, \right|+c\]

    D)                 \[\frac{1}{\sqrt{2}}\log \left| \tan \left( \frac{x}{2}-\frac{\pi }{8} \right)\, \right|+c\]

    Correct Answer: A

    Solution :

                       We have, \[I=\int_{{}}^{{}}{\frac{dx}{\cos x-\sin x}=\frac{1}{\sqrt{2}}\int_{{}}^{{}}{\frac{{{d}^{2}}}{\cos \left( \frac{\pi }{4}+x \right)}}}\]                    \[I=\frac{1}{\sqrt{2}}\int_{{}}^{{}}{\sec \left( x+\frac{\pi }{4} \right)}\,dx=\frac{1}{\sqrt{2}}\log \left| \tan \left( \frac{\pi }{4}+\frac{x}{2}+\frac{\pi }{8} \right)\, \right|+c\]                 \[I=\frac{1}{\sqrt{2}}\log \left| \tan \left( \frac{x}{2}+\frac{3\pi }{8} \right)\, \right|+c\].


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