JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Integration of Rational Function by Using Partial Fractions

  • question_answer
    \[\int_{{}}^{{}}{\frac{dx}{{{x}^{2}}+2x+2}=}\]                                        [Karnataka CET 2004]

    A)                 \[{{\sin }^{-1}}(x+1)+c\]

    B)                 \[{{\sinh }^{-1}}(x+1)+c\]

    C)                 \[{{\tanh }^{-1}}(x+1)+c\]

    D)                 \[{{\tan }^{-1}}(x+1)+c\]

    Correct Answer: D

    Solution :

                    \[\int_{{}}^{{}}{\frac{dx}{{{x}^{2}}+2x+2}=\int_{{}}^{{}}{\frac{dx}{{{(x+1)}^{2}}+1}={{\tan }^{-1}}(x+1)+c}}\].


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