JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Integration of Rational Function by Using Partial Fractions

  • question_answer
    \[\int_{{}}^{{}}{\frac{dx}{x({{x}^{n}}+1)}=}\]          [Roorkee 1979]

    A)                 \[n\log \frac{{{x}^{n}}}{{{x}^{n}}+1}+c\]

    B)                 \[n\log \frac{{{x}^{n}}+1}{{{x}^{n}}}+c\]

    C)                 \[\frac{1}{n}\log \frac{{{x}^{n}}}{{{x}^{n}}+1}+c\]

    D)                 \[\frac{1}{n}\log \frac{{{x}^{n}}+1}{{{x}^{n}}}+c\]

    Correct Answer: C

    Solution :

                       Put \[{{x}^{n}}=t\Rightarrow n{{x}^{n-1}}dx=dt\]                    \[\Rightarrow \frac{n{{x}^{n}}}{x}\,dx=dt\Rightarrow \frac{1}{x}\,dx=\frac{dt}{nt},\] then it reduces to                    \[\int_{{}}^{{}}{\frac{dt}{nt(t+1)}}=\frac{1}{n}\left[ \int_{{}}^{{}}{\frac{dt}{t(t+1)}} \right]\]                                      \[=\frac{1}{n}\left[ \int_{{}}^{{}}{\frac{1}{t}\,dt-\int_{{}}^{{}}{\frac{1}{t+1}\ dt}} \right]=\frac{1}{n}\log \frac{{{x}^{n}}}{{{x}^{n}}+1}+c\].


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