A) \[\log \frac{x+2}{x+1}+c\]
B) \[\log (x+1)+\log (x+2)+c\]
C) \[\log \frac{x+1}{x+2}+c\]
D) None of these
Correct Answer: C
Solution :
\[\int_{{}}^{{}}{\frac{dx}{(x+1)(x+2)}}=\int_{{}}^{{}}{\left( \frac{1}{x+1}-\frac{1}{x+2} \right)}\,dx\] \[=\log (x+1)-\log (x+2)+c=\log \frac{x+1}{x+2}+c.\]You need to login to perform this action.
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