A) 1 : 16
B) 1 : 4
C) 4 : 1
D) 2 : 1
Correct Answer: B
Solution :
\[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)}^{2}}=\frac{1}{16}\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{4}\]You need to login to perform this action.
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