• # question_answer A gas engine has a swept volume of 300 cc and clearance volume of 25 cc. Its volumetric efficiency is 0.88 and mechanical efficiency is 0.90. What is the volume of the mixture taken in per Stroke? A) 248 cc              B) 252 ccC) 264 cc              D) 286 cc

${{\eta }_{Vol}}=1+\frac{{{V}_{c}}}{{{V}_{s}}}=0.88$ ${{V}_{c}}+{{V}_{s}}=0.88\,\,{{V}_{s}}=0.88\times 300=264\,\,c.\,c$