A) Primary amine
B) Secondary amine
C) Tertiary amine
D) All of these
Correct Answer: D
Solution :
\[{{C}_{3}}{{H}_{9}}N\]Can form all the 3 amines. \[\underset{{{1}^{o}}\,\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-N{{H}_{2}}}}\,\], \[\underset{{{2}^{o}}\text{amine}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-NH-C{{H}_{3}}}}\,\] \[\underset{{{3}^{o}}\text{amine}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{N}}\,}}\,-C{{H}_{3}}}}\,\]
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