A) 9 sigma bonds and 4 pi bonds
B) 8 sigma bonds and 5 pi bonds
C) 8 sigma bonds, 3 pi bonds and 4 non-bonding electrons
D) 9 sigma bonds, 3 pi bonds and 2 non-bonding electrons
Correct Answer: D
Solution :
Allyl isocyanide. \[C{{H}_{2}}=CH-C{{H}_{2}}-N\vec{=}C\]
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