• # question_answer 15) DIRECTION: A courier person cycles from a town to a neighbouring sub-urban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph, During which period did he ride fastest? A)  9 a.m. - 10 a.m.B)  10 a.m. - 11 a.m.C)  8 a.m. - 9 a.m.D)  11 a.m. - 11:30 a.m.

Correct Answer: C

Solution :

Speed during 8 a.m. - 9 a:m.                                     = 10/1 = 10 km/h Speed during 9a.m. -10a.m. = 6/1 = 6km/h Speed during 10a.m. -11a.m. = 3/1 = 3km/h Speed during 11 a.m. - 11:30 a.m. $=\frac{3}{1/2}=6km/h$

LIMITED OFFER HURRY UP! OFFER AVAILABLE ON ALL MATERIAL TILL TODAY ONLY!

You need to login to perform this action.
You will be redirected in 3 sec