A) 3
B) 6
C) 12
D) 9
Correct Answer: D
Solution :
\[\text{192 }=\text{ 24 }\times \text{ 8 }+\text{ }0\]\[{{6}^{x}}\]and \[{{6}^{x}}={{(2\times 3)}^{x}}={{2}^{x}}\times {{3}^{x}}\] \[\Rightarrow \] \[{{6}^{x}}\] \[\therefore \]You need to login to perform this action.
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