A) \[\frac{3}{14}\]
B) \[\frac{3}{2}\]
C) \[\frac{1}{3}\]
D) \[\frac{1}{6}\]
Correct Answer: D
Solution :
\[\frac{\sin A}{\cos A}=\frac{4}{7}\] (Given) Now, \[\frac{7\sin A-3\cos A}{7\sin A+2\cos A}\] Dividing numerator and denominator by \[\cos A,\] we get \[\frac{\frac{7\sin A}{\cos A}-3}{\frac{7\sin A}{\cos A}+2}=\frac{7\times \frac{4}{7}-3}{7\times \frac{4}{7}+2}=\frac{1}{6}\]You need to login to perform this action.
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