A) \[\frac{\sqrt{3}}{2}\]
B) \[-\frac{\sqrt{3}}{2}\]
C) \[\frac{1}{2}\]
D) \[-\frac{1}{2}\]
Correct Answer: C
Solution :
\[\sin \,\left[ \frac{\pi }{2}-{{\sin }^{-1}}\left( -\frac{\sqrt{3}}{2} \right) \right]=\cos \,{{\sin }^{-1}}\left( -\frac{\sqrt{3}}{2} \right)\] \[=\cos \,{{\cos }^{-1}}\sqrt{1-\frac{3}{4}}=\frac{1}{2}\].
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