A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) 0
D) None of these
Correct Answer: D
Solution :
\[{{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3\] \[={{\tan }^{-1}}1+\pi +{{\tan }^{-1}}\left( \frac{5}{-5} \right)\]\[={{\tan }^{-1}}1+\pi -{{\tan }^{-1}}1=\pi \].You need to login to perform this action.
You will be redirected in
3 sec