A) 9 / 59
B) 2 / 3
C) 3 / 4
D) At constant volume \[P\propto T\]Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\]Þ\[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{300}{400}=\frac{3}{4}\]
Correct Answer: C
Solution :
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