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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Isobaric and Isochoric Processes

  • question_answer
    Work done by 0.1 mole of a gas at \[{{27}^{o}}C\] to double its volume at constant pressure is (R = 2 cal mol?1 oC?1) [EAMCET 1994]

    A)            54 cal                                       

    B)            600 cal

    C)            60 cal                                       

    D)            546 cal

    Correct Answer: C

    Solution :

               \[W=P\Delta V=nR\Delta T=0.1\times 2\times 300=60\ cal\]


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