A) Paramagnetism
B) Diamagnetism
C) Both A and B
D) None of these
Correct Answer: A
Solution :
\[M{{n}^{2+}}\] In presence of \[{{H}_{2}}O\]which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.You need to login to perform this action.
You will be redirected in
3 sec