A) \[1.013\times {{10}^{5}}N/{{m}^{2}}\]
B) \[1.013\times {{10}^{6}}N/{{m}^{2}}\]
C) \[1.,013\times {{10}^{-11}}N/{{m}^{2}}\]
D) \[1.013\times {{10}^{11}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
\[{{E}_{\theta }}=P=1.013\times {{10}^{5}}N/{{m}^{2}}\]
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