A) Internal energy of the system decreases
B) Work done by the gas is positive
C) Work done by the gas is negative
D) Internal energy of the system increases
Correct Answer: C
Solution :
For isothermal process \[dU=0\]and work done \[=dW=P({{V}_{2}}-{{V}_{1}})\] \[\because \ {{V}_{2}}=\frac{{{V}_{1}}}{2}=\frac{V}{2}\]\ \[dW=-\frac{PV}{2}\]You need to login to perform this action.
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