A) 0.0091 joule
B) 0.0182 joule
C) ? 0.0091 joule
D) ? 0.0182 joule
Correct Answer: A
Solution :
It is an isothermal process. Hence work done \[=P({{V}_{2}}-{{V}_{1}})\] \[=1\times {{10}^{5}}\times (1.091-1)\times {{10}^{-6}}=0.0091\ J\]You need to login to perform this action.
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