A) 540 cal
B) 40 cal
C) Zero cal
D) 500 cal
Correct Answer: B
Solution :
Amount of heat given \[=540\ calories\] Change in volume \[\Delta V=1670\ c.c\] Atmospheric pressure \[P=1.01\times {{10}^{6}}\ dyne/c{{m}^{2}}\] Work done against atmospheric pressure \[W=P\Delta V\]\[=\frac{1.01\times {{10}^{6}}\times 1670}{4.2\times {{10}^{7}}}\approx 40\ cal\]You need to login to perform this action.
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