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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Isothermal Process

  • question_answer
    540 calories of heat convert 1 cubic centimeter of water at \[{{100}^{o}}C\] into 1671 cubic centimeter of steam at \[{{100}^{o}}C\] at a pressure of one atmosphere. Then the work done against the atmospheric pressure is nearly

    A)            540 cal                                    

    B)            40 cal

    C)            Zero cal                                  

    D)            500 cal

    Correct Answer: B

    Solution :

                       Amount of heat given \[=540\ calories\] Change in volume \[\Delta V=1670\ c.c\] Atmospheric pressure \[P=1.01\times {{10}^{6}}\ dyne/c{{m}^{2}}\] Work done against atmospheric pressure \[W=P\Delta V\]\[=\frac{1.01\times {{10}^{6}}\times 1670}{4.2\times {{10}^{7}}}\approx 40\ cal\]


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