2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank Isothermal Process

  • question_answer
    One mole of an ideal gas expands at a constant temperature of 300 K from an initial volume of 10 litres to a final volume of 20 litres. The work done in expanding the gas is (R = 8.31 J/mole-K)                        [MP PMT 1995; UPSEAT 2000]

    A)            750 joules                              

    B)            1728 joules

    C)            1500 joules                            

    D)            3456 joules

    Correct Answer: B

    Solution :

               \[{{W}_{iso}}=\mu RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}=1\times 8.31\times 300{{\log }_{e}}\frac{20}{10}=1728J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner