JEE Main & Advanced Physics Thermodynamical Processes Question Bank Isothermal Process

  • question_answer
    In an isothermal reversible expansion, if the volume of 96 gm of oxygen at 27°C is increased from 70 litres to 140 litres, then the work done by the gas will be

    A)            \[300\,R{{\log }_{10}}2\] 

    B)            \[81\,R{{\log }_{e}}2\]

    C)            \[900\,R{{\log }_{10}}2\] 

    D)            \[2.3\times 900\,R{{\log }_{10}}2\]

    Correct Answer: D

    Solution :

                       \[W=\mu RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}\]    \[=\left( \frac{m}{M} \right)RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}=2.3\times \frac{m}{M}RT{{\log }_{10}}\frac{{{V}_{2}}}{{{V}_{1}}}\]  \[=2.3\times \frac{96}{32}R\,\,(273+27)\,{{\log }_{10}}\frac{140}{70}=\,2.3\times 900R{{\log }_{10}}2\]


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