A) \[1672.5\ J\]
B) 1728 J
C) \[-1728J\]
D) \[-1572.5\ J\]
Correct Answer: D
Solution :
\[W=-\mu RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}=-1\times 8.31\times (273+0){{\log }_{e}}\left( \frac{22.4}{11.2} \right)\] \[=-\,8.31\times 273\times {{\log }_{e}}2\]\[=-1572.5J\] [\[\because \]\[{{\log }_{e}}2=0.693\]]
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