A) Isotope
B) Isomer
C) Isomorph
D) Isobar
Correct Answer: D
Solution :
\[_{1}{{H}^{3}}{{\to }_{2}}H{{e}^{3}}{{+}_{-1}}{{e}^{0}}\] \[_{1}{{H}^{3}}\] and \[_{2}H{{e}^{3}}\] are isobars (same mass no.)
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