A) iE = ? 1 mA, iB = 9 mA
B) iE = 9 mA, iB = ? 1 mA
C) iE = 1 mA, iB = 11 mA
D) iE = 11 mA, iB = 1 mA
Correct Answer: D
Solution :
\[{{i}_{C}}=\frac{90}{100}\times {{i}_{E}}\]Þ 10 = 0.9 ´ iE = 11mA Also \[{{i}_{E}}={{i}_{B}}+{{i}_{C}}\]\[\Rightarrow {{i}_{B}}=11-10=1mA.\]You need to login to perform this action.
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