JEE Main & Advanced Physics Semiconducting Devices Question Bank Junction Transistor

  • question_answer
    In a transistor in CE configuration, the ratio of power gain to voltage gain is          [J & K CET 2005]

    A)            a   

    B)            b / a

    C)            ba

    D)            b

    Correct Answer: D

    Solution :

               For CE configuration voltage gain \[=\beta \times {{R}_{L}}/{{R}_{i}}\] Power gain \[={{\beta }^{2}}\times {{R}_{L}}/{{R}_{i}}\] Þ \[\frac{\text{Power gain}}{\text{Voltage gain}}=\beta \]


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