JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Kepler's Laws of Planetary Motion

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    The largest and the shortest distance of the earth from the sun are \[{{r}_{1}}\] and \[{{r}_{2}}\], its distance from the sun when it is at the perpendicular to the major axis of the orbit drawn from the sun                                                [CBSE PMT 1991]

    A)             \[\frac{{{r}_{1}}+{{r}_{2}}}{4}\]

    B)             \[\frac{{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\]

    C)             \[\frac{2{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\] 

    D)             \[\frac{{{r}_{1}}+{{r}_{2}}}{3}\]

    Correct Answer: C

    Solution :

                    The earth moves around the sun is elliptical path. so by using the properties of ellipse             \[{{r}_{1}}=(1+e)\,a\] and \[{{r}_{2}}=(1-e)\,a\]             \[\Rightarrow \,a=\frac{{{r}_{1}}+{{r}_{2}}}{2}\] and \[{{r}_{1}}{{r}_{2}}=(1-{{e}^{2}})\,{{a}^{2}}\] where a = semi major axis b = semi minor axis e = eccentricity Now required distance = semi latusrectum \[=\frac{{{b}^{2}}}{a}\]             \[=\frac{{{a}^{2}}(1-{{e}^{2}})}{a}=\frac{({{r}_{1}}{{r}_{2}})}{({{r}_{1}}+{{r}_{2}})/2}=\frac{2{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\]


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