JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Kepler's Laws of Planetary Motion

  • question_answer
    The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be      [MP PMT 1994]

    A) 83 minutes

    B)               \[83\times \sqrt{8}\] minutes

    C)             664 minutes

    D)               249 minutes

    Correct Answer: C

    Solution :

                    For first satellite \[{{r}_{1}}=R\] and \[{{T}_{1}}=83\ minute\] For second satellite \[{{r}_{2}}=4R\]             \[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{3/2}}={{T}_{1}}{{(4)}^{3/2}}=8{{T}_{1}}=8\times 83\]=664 minutes


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