JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Kepler's Laws of Planetary Motion

  • question_answer
    A satellite of mass m is circulating around the earth with constant angular velocity. If radius of the orbit is \[{{R}_{0}}\] and mass of the earth M, the angular momentum about the centre of the earth is       [MP PMT 1996; RPMT 2000]

    A)             \[m\sqrt{GM{{R}_{0}}}\]

    B)               \[M\sqrt{Gm{{R}_{0}}}\]

    C)             \[m\sqrt{\frac{GM}{{{R}_{0}}}}\] 

    D)             \[M\sqrt{\frac{GM}{{{R}_{0}}}}\]

    Correct Answer: A

    Solution :

        Angular momentum = Mass ×Orbital velocity ×Radius             \[=m\times \left( \sqrt{\frac{GM}{{{R}_{0}}}} \right)\times {{R}_{0}}=m\sqrt{GM{{R}_{0}}}\]


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