A) 83 minutes
B) \[83\times \sqrt{8}\] minutes
C) 664 minutes
D) 249 minutes
Correct Answer: C
Solution :
For first satellite \[{{r}_{1}}=R\] and \[{{T}_{1}}=83\ minute\] For second satellite \[{{r}_{2}}=4R\] \[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{3/2}}={{T}_{1}}{{(4)}^{3/2}}=8{{T}_{1}}=8\times 83\]=664 minutesYou need to login to perform this action.
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