JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Kepler's Laws of Planetary Motion

  • question_answer
    A satellite A of mass m is at a distance of r from the centre of the earth. Another satellite B of mass 2m is at a distance of 2r from the earth's centre. Their time periods are in the ratio of                 [CBSE PMT 1993]

    A) 1 : 2    

    B)             1 : 16

    C)             1 : 32  

    D)             \[1:2\sqrt{2}\]

    Correct Answer: D

    Solution :

                    Mass of the satellite does not effects on time period             \[\frac{{{T}_{A}}}{{{T}_{B}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3/2}}={{\left( \frac{r}{2r} \right)}^{3/2}}={{\left( \frac{1}{8} \right)}^{1/2}}=\frac{1}{2\sqrt{2}}\]


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