A) Half the present year
B) One-eighth the present year
C) One-fourth the present year
D) One-sixth the present year
Correct Answer: B
Solution :
Since \[{{T}^{2}}\propto {{r}^{3}}\]\[\therefore \,\,{{\left( \frac{{{T}'}}{T} \right)}^{2}}={{\left( \frac{1}{4} \right)}^{3}}\,\Rightarrow \,{T}'=\frac{1}{8}T\]
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