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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of \[1\,m{{s}^{-2}}\]. If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is                         [SCRA 1998]

    A)                         3000 N            

    B)                         4000 N            

    C)                         5000 N            

    D)                                       6000 N          

    Correct Answer: D

    Solution :

                                Net force in forward direction = Accelerating force + Friction               \[=ma+\mu \ mg=m(a+\mu \ g)=(1500+500)(1+0.2\times 10)\]               \[=2000\times 3=6000\ N\]


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