A) \[\mu Rg\]
B) \[Rg\sqrt{\mu }\]
C) \[\mu \sqrt{Rg}\]
D) \[\sqrt{\mu Rg}\]
Correct Answer: D
Solution :
In the given condition the required centripetal force is provided by frictional force between the road and tyre. \[\frac{m{{v}^{2}}}{R}=\mu \,mg\] \[\therefore \] \[v=\sqrt{\mu \ Rg}\]
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