JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction m = 0.5.  If a horizontal force of 100 N is acting on it, then acceleration of the block will be                             [AIIMS 2002]

    A)             \[0.5m/{{s}^{2}}\]  

    B)             \[5m/{{s}^{2}}\]

    C)             \[10m/{{s}^{2}}\]   

    D)             \[15m/{{s}^{2}}\]

    Correct Answer: B

    Solution :

                    \[a=\frac{\text{Applied force --Kinetic friction}}{\text{mass}}\]             \[=\frac{100-0.5\times 10\times 10}{10}=5m/{{s}^{2}}\]


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