JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s.  Then the coefficient of friction is                                     [AIEEE 2003]

    A)             0.01    

    B)             0.02

    C)             0.03    

    D)             0.06

    Correct Answer: D

    Solution :

                    \[v=u-at\Rightarrow u-\mu gt=0\] \[\therefore \] \[\mu =\frac{u}{gt}=\frac{6}{10\times 10}=0.06\]


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