A) \[0.26\,m/{{s}^{2}}\]
B) \[0.39\,m/{{s}^{2}}\]
C) \[0.69\,m/{{s}^{2}}\]
D) \[0.88\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
Net force = Applied force ? Friction force \[ma=24-\mu \ mg\]\[=24-0.4\times 5\times 9.8\]\[=24-19.6\] Þ \[a=\frac{4.4}{5}=0.88\ m/{{s}^{2}}\]
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