JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A body of mass 5kg rests on a rough horizontal surface of coefficient of friction 0.2.  The body is pulled through a distance of 10m by a horizontal force of 25 N.  The kinetic energy acquired by it is (g = 10 ms2) [EAMCET (Med.) 2000]

    A)             330 J  

    B)             150 J

    C)             100 J  

    D)             50 J

    Correct Answer: B

    Solution :

                    Kinetic energy acquired by body = (Total work done on the body) ? (work against friction)      \[=F\times S-\mu mgS=25\times 10-0.2\times 5\times 10\times 10\] \[=250-100=150\ Joule\]


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