A) \[6\,m/{{s}^{2}}\]
B) \[4.9\,m/{{s}^{2}}\]
C) \[3.92\,m/{{s}^{2}}\]
D) \[1\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
Limiting friction \[={{\mu }_{s}}R={{\mu }_{s}}mg=0.5\times 60\times 10=300\ N\] Kinetic friction \[={{\mu }_{k}}R={{\mu }_{k}}mg=0.4\times 60\times 10=240\ N\] Force applied on the body = 300 N and if the body is moving then, Net accelerating force =Applied force ? Kinetic friction Þ \[ma=300-240=60\] \[\therefore \] \[a=\frac{60}{60}=1\ m/{{s}^{2}}\]
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