Answer:
\[{{P}_{0}}=\frac{1}{3}\frac{mN}{V}{{\upsilon }^{2}}\] \[\therefore \] \[P'=\frac{1}{3}\frac{(m/2)}{V}{{(2\upsilon )}^{2}}=\frac{2}{3}\frac{mN}{V}{{\upsilon }^{2}}=\mathbf{2}{{\mathbf{P}}_{\mathbf{0}}}\]
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