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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoff's Law, Cells

  • question_answer
    When a resistance of 2ohm is connected across the terminals of a cell, the current is 0.5 amperes. When the resistance is increased to 5 ohm, the current is 0.25 amperes. The internal resistance of the cell is                                   [MP PMT 1996]

    A)                    \[0.5\,ohm\]

    B)                                      \[1.0\,ohm\]

    C)                    \[1.5\,ohm\]                

    D)            \[2.0\,ohm\]

    Correct Answer: D

    Solution :

               Let the e.m.f. of cell be E and internal resistance be r. Then \[0.5=\frac{E}{(r+2)}\] and \[0.25=\frac{E}{(r+5)}\] On dividing, \[2=\frac{5+r}{2+r}\] Þ \[r=1\Omega \]


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