2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर

JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoff's Law, Cells

  • question_answer
    The potential difference in open circuit for a cell is 2.2 volts. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be                                             [MP PMT 1984; SCRA 1994; CBSE PMT 2002]

    A)                    1 ohm

    B)                                      0.2 ohm

    C)                    2.5 ohm                          

    D)            0.4 ohm

    Correct Answer: D

    Solution :

               \[(4+r)i=2.2\]      ......(i) and \[4i=2\] Þ \[i=\frac{1}{2}\] Putting the value of i in (i), we get r = 0.4 ohm.


You need to login to perform this action.
You will be redirected in 3 sec spinner