question_answer

The magnitude and direction of the current in the circuit shown will be                                  [CPMT 1986, 88]

A)                    \[\frac{7}{3}\]A from a to b through e

B)                    \[\frac{7}{3}\]A from b to a through e

C)                    1A from b to a through e

D)                    1A from a to b through e            

Correct Answer: D

Solution :

           Since \[{{E}_{1}}(10\,V)>{{E}_{2}}(4V)\] So current in the circuit will be clockwise. Applying Kirchoff's voltage law \[-\,1\times i+10-4-2\times i-3i=0\] Þ \[i=1A(a\,\text{to }b\text{ via }e)\] \ Current \[=\frac{V}{R}=\frac{10-4}{6}=1.0\,ampere\]