A) 10
B) 100
C) 500
D) 200
Correct Answer: B
Solution :
For no current through galvanometer, we have \[\left( \frac{{{E}_{1}}}{500+X} \right)X=E\] Þ \[\left( \frac{12}{500+X} \right)X=2\] Þ \[X=\text{ }100\Omega \]You need to login to perform this action.
You will be redirected in
3 sec