A) \[0.5\,ohm\]
B) \[1.0\,ohm\]
C) \[1.5\,ohm\]
D) \[2.0\,ohm\]
Correct Answer: D
Solution :
Let the e.m.f. of cell be E and internal resistance be r. Then \[0.5=\frac{E}{(r+2)}\] and \[0.25=\frac{E}{(r+5)}\] On dividing, \[2=\frac{5+r}{2+r}\] Þ \[r=1\Omega \]You need to login to perform this action.
You will be redirected in
3 sec