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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoffs Law Cells

  • question_answer
    A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10V, the potential of positive electrode will be                                                                                          [MP PMT 1997]

    A)                    5 V                                    

    B)            14 V

    C)                    15 V                                  

    D)            16 V

    Correct Answer: B

    Solution :

               \[{{V}_{2}}-{{V}_{1}}=E-ir=5-2\times 0.5=4volt\] Þ \[{{V}_{2}}=4+{{V}_{1}}=4+10=14\,volt\]


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