A) 5 amp
B) 3 amp
C) \[-3\,amp\]
D) \[-5/6\,amp\]
Correct Answer: D
Solution :
Suppose current through different paths of the circuit is as follows. After applying KVL for loop (1) and loop (2) We get \[28{{i}_{1}}=-6-8\] Þ \[{{i}_{1}}=-\frac{1}{2}A\] and \[54{{i}_{2}}=-6-12\] Þ \[{{i}_{2}}=-\frac{1}{3}A\] Hence \[{{i}_{3}}={{i}_{1}}+{{i}_{2}}=-\frac{5}{6}A\]You need to login to perform this action.
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