A) 1 amp
B) 2 amp
C) 4 amp
D) Infinite
Correct Answer: B
Solution :
\[i=\frac{E}{R+r}\Rightarrow 1=\frac{4}{2+r}=r=2\Omega \] Short circuit when terminals of battery connected directly then current flows which is \[{{i}_{SC}}=\frac{E}{r}=\frac{4}{2}=2A\].You need to login to perform this action.
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